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0=0.7x^2-28x-1075
We move all terms to the left:
0-(0.7x^2-28x-1075)=0
We add all the numbers together, and all the variables
-(0.7x^2-28x-1075)=0
We get rid of parentheses
-0.7x^2+28x+1075=0
a = -0.7; b = 28; c = +1075;
Δ = b2-4ac
Δ = 282-4·(-0.7)·1075
Δ = 3794
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-\sqrt{3794}}{2*-0.7}=\frac{-28-\sqrt{3794}}{-1.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+\sqrt{3794}}{2*-0.7}=\frac{-28+\sqrt{3794}}{-1.4} $
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